To find the fraction of the cars that are less than 4 years old which also get at least 60 miles to the gallon, we will set up our problem using the information given.
Let \( C \) be the total number of cars in the used-car lot.
According to the problem:
- The number of cars that are less than 4 years old is \( \frac{3}{4}C \).
- The number of cars that are both less than 4 years old and get at least 60 miles to the gallon is \( \frac{1}{4}C \).
Now we need to find the fraction of the cars that are less than 4 years old which also get at least 60 miles to the gallon. This can be calculated by taking the number of cars that are both less than 4 years old and get at least 60 mpg, divided by the number of cars that are less than 4 years old.
The fraction is computed as follows:
\[ \text{Fraction} = \frac{\text{Number of cars less than 4 years old and get at least 60 mpg}}{\text{Number of cars less than 4 years old}} = \frac{\frac{1}{4}C}{\frac{3}{4}C} \]
Since \( C \) appears in both the numerator and the denominator, we can simplify:
\[ \text{Fraction} = \frac{\frac{1}{4}}{\frac{3}{4}} = \frac{1}{4} \cdot \frac{4}{3} = \frac{1}{3} \]
Thus, the fraction of the cars that are less than 4 years old which also get at least 60 miles to the gallon is
\[ \boxed{\frac{1}{3}}. \]