To solve this problem, we can set up a proportion relationship between the number of students in Ms. Darnell's class and the number of students with an A.
Let x represent the number of students in Ms. Jay's homeroom who would be expected to have an A.
The proportion can be set up as:
9/72 = x/16
To solve for x, we can cross-multiply and divide:
72x = 9 * 16
72x = 144
Dividing both sides by 72:
x = 144/72
x = 2
Therefore, we would expect 2 students out of the 16 in Ms. Jay's homeroom to have an A.
Of the 72 students who have Ms. Darnell for health/PE, 9 have an A. at this rate, how many of the 16 students in Ms.jay's homeroom would you expect to have an A show your work in number form
1 answer
1 answer