Of the 42 kids who entered the race 35 finished. If the sum of all the finishing times was 8 2/5 hours, what was the average finishing time?

1 answer

To find the average finishing time, we need to divide the total finishing time by the number of kids who finished the race.

Given:

  • Number of kids who finished = 35
  • Total finishing time = \( 8 \frac{2}{5} \) hours

First, convert \( 8 \frac{2}{5} \) hours into an improper fraction or a decimal.

The mixed number \( 8 \frac{2}{5} \) can be converted as follows:

\[ 8 = \frac{40}{5} \] \[ 8 \frac{2}{5} = \frac{40}{5} + \frac{2}{5} = \frac{42}{5} \]

Now, using this total time, we can calculate the average finishing time:

\[ \text{Average finishing time} = \frac{\text{Total finishing time}}{\text{Number of finishers}} = \frac{\frac{42}{5}}{35} \]

To divide \( \frac{42}{5} \) by \( 35 \), convert \( 35 \) to a fraction:

\[ 35 = \frac{35}{1} \]

Now, we divide fractions by multiplying by the reciprocal:

\[ \frac{42}{5} \div \frac{35}{1} = \frac{42}{5} \times \frac{1}{35} = \frac{42 \times 1}{5 \times 35} = \frac{42}{175} \]

Next, simplify \( \frac{42}{175} \). First, we need to find the greatest common divisor (GCD) of 42 and 175.

The prime factorization of 42 is \( 2 \times 3 \times 7 \). The prime factorization of 175 is \( 5 \times 5 \times 7 \) or \( 5^2 \times 7 \). The GCD is \( 7 \).

Now divide both the numerator and the denominator by 7:

\[ \frac{42 \div 7}{175 \div 7} = \frac{6}{25} \]

Thus, the average finishing time in hours is:

\[ \frac{6}{25} \text{ hours} \]

To convert \( \frac{6}{25} \) hours into minutes, we multiply by 60 (since there are 60 minutes in an hour):

\[ \frac{6}{25} \times 60 = \frac{6 \times 60}{25} = \frac{360}{25} = 14.4 \text{ minutes} \]

To summarize, the average finishing time is:

\[ \text{Average finishing time} = \frac{6}{25} \text{ hours} \text{ or } 14.4 \text{ minutes} \]

So the final answer is:

\[ \frac{6}{25} \text{ hours} \] or approximately 14 minutes and 24 seconds.