Of 500 employees of a firm 280 have a life insurance policy ,400 have a medical insurance cover and 200 participate in both programs.

Question

1)what is the probability that a randomly selected employee will be a participant in at least one of the two programs ?
2)Determine the probability that an employee will be a participant in the life insurance plan given that he/she has a medical insurance coverage?

Answer 1

Pr(one of them)=(280+400-200)/500
= 480/500

Pr(life given medical)=80/400

Answer 2

pr 480/500

Answer 3

1) Addition rule
(280/500)+(400/500)-(200/500)
=480/500