first find the probability of all 3 blue eyes
= C(10,3) / C(27,3) = 120/2925 = 8/195
so prob(no blue eyes) = 1 - 8/195 = 187/195
The the odds in favour of all being blue eyes = (8/195) : 187/195
= 8 : 187
Of 27 students in a class, 10 have blue eyes , 14 have brown eyes , and
3 have green eyes. If 3 students are chosen at random .
what are the odds of all three have blue eyes?
3 answers
Not very nice to pass on somebody's else solution as your own !
I agree with Reiny.
MEF/sara/hola — not too smart to keep switching names.
Connexus student — a plagiarizer
https://www.jiskha.com/questions/1823069/of-27-students-in-a-class-10-have-blue-eyes-14-have-brown-eyes-and-3-have-green-eyes
MEF/sara/hola — not too smart to keep switching names.
Connexus student — a plagiarizer
https://www.jiskha.com/questions/1823069/of-27-students-in-a-class-10-have-blue-eyes-14-have-brown-eyes-and-3-have-green-eyes