Objects with masses m1 = 11.0 kg and m2 = 6.0 kg are connected by a light string that passes over a friction-less pulley as in the figure below. If, when the system starts from rest, m2 falls 1.00 m in 1.48 s, determine the coefficient of kinetic friction between m1 and the table.

Answer 1

6 g - T = 17 a

T - mu(11 g) = 11 a

what is a?
d = (1/2) a t^2
1 = (1/2)a(1.48)^2
a = .913 m/s^2

6 g - T = 15.5 so T = 6 g - 15.5
so
6 g - 15.5 - 11 g mu = 10.0
let g = 9.8 and solve for mu