Object Mass (grams) paper clip 1.0 penny 2.5 book 860 cereal box 500 small pot 1,200 Between which two objects is gravitational attraction the greatest if placed 1 meter apart? (1 point) Responses between the penny and the small pot between the penny and the small pot between the paper clip and the penny between the paper clip and the penny between the book and the cereal box between the book and the cereal box between the small pot and the book

1 answer

To determine between which two objects gravitational attraction is the greatest when placed 1 meter apart, we can use the formula for gravitational force:

\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]

where:

  • \( F \) is the gravitational force,
  • \( G \) is the gravitational constant,
  • \( m_1 \) and \( m_2 \) are the masses of the two objects,
  • \( r \) is the distance between the centers of the two masses.

Since the distance \( r \) is constant (1 meter), the gravitational force will be proportional to the product of the masses \( m_1 \) and \( m_2 \). Therefore, we need to compare the products of the masses for the pairs of objects given.

Here are the masses of the objects:

  • Paper clip: 1.0 grams
  • Penny: 2.5 grams
  • Book: 860 grams
  • Cereal box: 500 grams
  • Small pot: 1200 grams

Now we calculate the products for each pair:

  1. Penny and Small Pot: \[ 2.5 \times 1200 = 3000 \]

  2. Paper Clip and Penny: \[ 1.0 \times 2.5 = 2.5 \]

  3. Book and Cereal Box: \[ 860 \times 500 = 430000 \]

  4. Small Pot and Book: \[ 1200 \times 860 = 1032000 \]

Now, comparing all the products, we find:

  • Penny and Small Pot: 3000
  • Paper Clip and Penny: 2.5
  • Book and Cereal Box: 430000
  • Small Pot and Book: 1032000

The greatest product is between the Small Pot and the Book with a product of 1,032,000 gramsĀ². Thus, the gravitational attraction is greatest between the small pot and the book when placed 1 meter apart.