X = Distance travelled = (1/2) a t^2
The acceleration a is the same for both. If t is twice as long for object B, what does this do to the value of X?
Object A and B both start at rest. They both accelerate at the same rate. However , object A accelerates for twice the time as object B. What is the distance traveled by object A compared to that of object B?
a) the same distance
B) twice as far
c) three times as far
d) four times as far
Which equation would i use to test out this situation?
2 answers
four time as far
1 answer