Since M is the mid-point of OB, we have:
(MA) ⃗ = (MO) ⃗ + (OA) ⃗
Since OABC is a parallelogram, we have:
(MO) ⃗ = (OC) ⃗ = c
Therefore,
(MA) ⃗ = c + a
So, in terms of a and c, (MA) ⃗ is equal to c + a.
OABC is a parallelogram. (OA) ⃗ = a and (OC) ⃗ = c
M is the mid-point of OB.
Find (MA) ⃗ in terms of a and c.
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