lots of assumptions here, nevertheless, ...
Assumption #1 : ignore certain restrictions on plate names,
e.g. a lot of 4-letter words would not be allowed.
number of different plates
= 26^4 * 10^3
= 456976000
no. of cars in NY currently = 12929000*(560/1000)
= 7240240
Assumption #2 : the ratio of cars:people remains constant at 560:1000
Assumption #3 : the growth rate is per annum
then 7240240(1.02)^t = 456976000
1.02^t = 63.116
t = log 63.116/log 1.02
= 209.3 years
Assumption #4 : Do you think that in about 200 from now we would still have "cars" with metal plates attached to identify them ??
NY has 560 cars for 1000 residents. The current population of NY is 12,929,000 and rate of growth of the population is 0.02%. NY license plates consists of 4 letters followed by 3 digits. What year will they need to change the way they make license plates?
5 answers
Hi I got 20, 000 years... The rate is 0.02% which is 0.02/100 ?
then 7240240(1.02)^t = 456976000
1.02^t = 63.116
t = log 63.116/log 1.02
= 209.3 years
How did you get that? Thanks!
then 7240240(1.02)^t = 456976000
1.02^t = 63.116
t = log 63.116/log 1.02
= 209.3 years
How did you get that? Thanks!
you are right, I read the rate incorrectly
so my equation should have been
7240240(1.0002)^t = 456976000
1.0002^t = 63.1161398
log(1.0002^t) = log63.1161398
t(log(1.0002)) = log63.1161398
t = log63.1161398/log1.0002
t = 20727 years
using logs is the only way actually solve the equation.
The other way would be by trial and error, a very time-consuming way.
so my equation should have been
7240240(1.0002)^t = 456976000
1.0002^t = 63.1161398
log(1.0002^t) = log63.1161398
t(log(1.0002)) = log63.1161398
t = log63.1161398/log1.0002
t = 20727 years
using logs is the only way actually solve the equation.
The other way would be by trial and error, a very time-consuming way.
Thanks for your help! Much appreciated :)!
and in 20K years... Will they still even have cars xD?