When we take the first number out of the bag, there are 20 numbers and 10 of them are odd. So, the probability of drawing an odd number is 10/20 or 1/2.
Since the first number is not replaced, there will be 19 numbers left in the bag, including 9 even numbers. Thus, the probability of drawing an even number after drawing an odd number on the first draw is 9/19.
The probability of these two events happening together is the product of their probabilities:
P(Odd on first draw) * P(Even on second draw | Odd on first draw)
= (10/20) * (9/19)
= 9/38
Therefore, the probability of drawing an odd number on the first draw and an even number on the second draw is 9/38.
Numbers 1 to 20 are placed in a bag. Without replacing the first number, what is the probability that the first number drawn will be odd and the second one will be even?
1 answer