The total number of balls selected from Bowl B is 60 white balls + 40 red balls = 100 balls.
Since there are 500 balls in Bowl B, the fraction of white balls selected from Bowl B is 60 white balls / 100 total balls = 0.6.
Therefore, the estimated number of white balls in Bowl B is 0.6 * 500 balls = 300 white balls.
Similarly, the estimated number of red balls in Bowl B is 0.4 * 500 balls = 200 red balls.
The estimated difference in the expected number of white and red balls in Bowl B is 300 white balls - 200 red balls = 100 balls.
Therefore, the correct answer is 100.
Number of white balls selected
Bowl A: 45
Bowl B: 60
Number of red balls selected
Bowl A: 55
Bowl B: 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
200
50
100
300
1 answer