Number of possible turning points in the following equation
f(x)=x^2(x-3)(x+4)
show work please
4 answers
Sorry, I only do the non-URGENT ones
look at the factors. THere is a turning point at 3, -4. At zero, f(x) keeps the same curvature.
so does that mean there are 2 turning points
Number of possible turning points in the following equation
f(x)=x^2(x-3)(x+4)
are there 2 turning points or three turning points on the graph
f(x)=x^2(x-3)(x+4)
are there 2 turning points or three turning points on the graph