I would rather show you how to do it.
mols CO2 = grams CO2/molar mass CO2 = ?
Then there are 2 mols O atoms for every mols CO2
Then there are 6.02E23 O atoms in a mols of O atoms.
Unless I punched in the wrong numbers on my calculator, the correct answer isn't there.
Number of Oxygen atoms in 4.4g of CO2 is
A)1.2×10^13
B)6×10^22
C)6×10^23
D)12×10^23
Please tell me correct option with the solution.
2 answers
molar mass of CO2=44g/mol
We have 4.4g
n= 4.4÷44=0.1mol
CO2=0.1×6.022×10^23molecules
=6.022×10^22 molecules
1 molecule of CO2 contains 2atoms of Oxygen
6.022×10^22 molecules would contain
6.022×10^22×2=1.204×10^23
that is 1.2×10^23
We have 4.4g
n= 4.4÷44=0.1mol
CO2=0.1×6.022×10^23molecules
=6.022×10^22 molecules
1 molecule of CO2 contains 2atoms of Oxygen
6.022×10^22 molecules would contain
6.022×10^22×2=1.204×10^23
that is 1.2×10^23