number of O atom if 500g Au(NO3) 3

Answer 1

How many moles in 500 g Au(NO3)3? That's
mols = 500/molar mass Au(NO3)3. Then molecules Au(NO3)3 = mols Au(NO3)3 x 6.02E23.
Finally, number of O atoms will be 9 x number of atoms Au(NO3)3. Put it all together. 500/molar mass Au(NO3)3 x 6.02E23 molecules Au(NO3)3/mol x 9 O atoms/mol Au(NO3)3 = ?