number of atoms in 3.227*10^10 mol of potassium

Answer 1

There are 1.948 x 10^29 atoms in 3.227 x 10^10 mol of potassium.

To calculate this:

1. Start with Avogadro's constant, which is the number of atoms in one mole of a substance: 6.022 x 10^23 atoms/mol.

2. Multiply Avogadro's constant by the number of moles of potassium:

6.022 x 10^23 atoms/mol * 3.227 x 10^10 mol = 1.948 x 10^29 atoms