Nth expression for the following:6,11,17,24,32.....
2 answers
41 it goes up a number each time
The numbers represent the following sequence
n........1...2...3...4...4...
.........6..11..17..24..32...
1st diff...5...6...7...8
2nd dif......1...1...1
With the 2nd differences equal to 1, the general form of the equation defining the Nth term is a quadratic of the form N = an^2 + bn + c. Using the given data we can write
1 + b + c = 6
4a + 2b + c = 11
9a + 3b + c = 17
Solving yields a = 1/2, b 7/2 and c = 2 making the general expression for the Nth term N = (n^2 + 7n + 4)/2.
Thus, the sequence continues as
6, 11, 17, 24, 32, 41, 51, 62, 74...
n........1...2...3...4...4...
.........6..11..17..24..32...
1st diff...5...6...7...8
2nd dif......1...1...1
With the 2nd differences equal to 1, the general form of the equation defining the Nth term is a quadratic of the form N = an^2 + bn + c. Using the given data we can write
1 + b + c = 6
4a + 2b + c = 11
9a + 3b + c = 17
Solving yields a = 1/2, b 7/2 and c = 2 making the general expression for the Nth term N = (n^2 + 7n + 4)/2.
Thus, the sequence continues as
6, 11, 17, 24, 32, 41, 51, 62, 74...
1 answer