h = 0.5g*t^2
h = 2 m.
g = 9.8 m/s^2
t = Fall time.
Solve for t.
Dx = Xo * t
Dx = Hor. distance from table.
Xo = 10m/s = Initial hor. velocity.
Solve for Dx.
Now how far the will the ball in the problem below will hit the ground?
a. 10m
b. 6.4m
c. 9.6m
d. 20m
e. 140m
a ball rolls off the table top 2m tall. with a velocity of 10m/s. with what speed will it strike the ground?
V^2 = Vo^2 + 2g*h
V^2=0^2+2*9.8*2
V^2=39.2^2
v=6.3m/s
1 answer