Now have to mix this solution of urea and Shulphuric acid reagent in my previous question to rock phosphate 27percent in a molar ratio of 2.8 moles of Shulphuric acid to one mole of rock phosphate? How much rock and how much reagent will be used

Answer 1

To calculate the amount of rock phosphate and reagent needed, we can use the given molar ratio of 2.8 moles of sulfuric acid to 1 mole of rock phosphate.

Let's assume we have 1 mole of rock phosphate. According to the molar ratio, we would need 2.8 moles of sulfuric acid to mix with it.

Now, let's convert the moles of sulfuric acid to mass using their molar mass:
- Rock phosphate (27% P2O5) has a molar mass of approximately 309.9 g/mol.
- Sulfuric acid (H2SO4) has a molar mass of approximately 98.1 g/mol.

1 mole of rock phosphate = 309.9 g
2.8 moles of sulfuric acid = 2.8 * 98.1 = 275.88 g

Therefore, in the molar ratio of 2.8 moles of sulfuric acid to 1 mole of rock phosphate, you would need 309.9 g of rock phosphate and 275.88 g of sulfuric acid to mix the solution.