Now a peg is placed 4/5 of the way down the pendulum’s path so that when the mass falls to its vertical position it hits and wraps around the peg.
How fast is the mass moving when it is at the same vertical height as the peg (directly to the right of the peg)?
v=2.3 T=21.8
so far I have that the rope is .2696m long, the mass is .740kg
I saw that I could potentially use the formula v=(2gH)^(1/2) but I don't know what to plug into the H... is that even the right formula?
1 answer
update: I got it, the answer is 2.03
1 answer