To solve the equation 3(x+2)√5 + 3 = 27, we follow these steps:
1. Subtract 3 from both sides of the equation:
3(x+2)√5 = 24
2. Divide both sides by 3:
(x+2)√5 = 8
3. Square both sides to eliminate the square root:
(x+2)√5)^2 = 8^2
(x+2)*5 = 64
5x + 10 = 64
4. Subtract 10 from both sides:
5x = 54
5. Divide by 5 to solve for x:
x = 54/5
Therefore, the solution to the equation 3(x+2)√5 + 3 = 27 is x = 54/5.
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What is the solution of the equation?
3(x+2)3−−−−−−−√5+3=27
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