There are six possible outcomes when rolling a number cube: 1, 2, 3, 4, 5, and 6.
To find P(even, then not 2), we need to determine the number of outcomes that are even and not 2, and then divide that by the total number of possible outcomes when rolling the number cube twice.
First, let's determine the number of outcomes that are even and not 2.
Even numbers are 2, 4, and 6. Out of these three even numbers, only one is not 2, which is 4. Therefore, there is only one outcome that is even and not 2.
Next, we need to find the total number of possible outcomes when rolling the number cube twice. This can be determined by multiplying the number of outcomes for each roll. Since there are six possible outcomes for each roll, the total number of possible outcomes is 6 x 6 = 36.
Finally, we can find the probability of rolling an even number, then not 2, by dividing the number of outcomes that meet the requirements (1) by the total number of possible outcomes (36):
P(even, then not 2) = 1/36
Therefore, the probability of rolling an even number, then not 2, is 1/36.
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You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
2 answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
A number cube is rolled 450 times. The number 3 comes up 67 times.
a. What is the theoretical probability of rolling a 3? Write your answer as a fraction in simplest form.
b. What is the experimental probability of rolling a 3? Write your answer as a fraction in simplest form.
A number cube is rolled 450 times. The number 3 comes up 67 times.
a. What is the theoretical probability of rolling a 3? Write your answer as a fraction in simplest form.
b. What is the experimental probability of rolling a 3? Write your answer as a fraction in simplest form.