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Question

Solve the system of equations algebraically. Show all of your steps.
y=x2+2x
y=3x+20

Answer 1

Since both equations are set equal to y, we can set them equal to each other:
x^2 + 2x = 3x + 20
Subtracting 3x and 20 from both sides, we get:
x^2 - x - 20 = 0
Factoring, we get:
(x - 5)(x + 4) = 0
Therefore, x = 5 or x = -4.
Substituting these values of x back into either equation, we can solve for y:
If x = 5:
y = 5^2 + 2(5) = 35
If x = -4:
y = (-4)^2 + 2(-4) = 8
Therefore, the solution to the system of equations is (5, 35) and (-4, 8).

Answer 2

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Answer 3

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