Not sure how to solve this:

Question

Suppose your school is selling magazine subscriptions. Each subscription cost $20. the company pays the school half of the total sales in dollars. The school must also pay a one-time fee of $18. What is the fewest number of subscriptions that can be sold to earn profit of $200?

200/2 =100

100 + 18 = 118/20 = 5.9 = 6 subscriptions?

Answer 1

No, the question is asking for the FEWEST account of magazines sold to make $200 for the school.

-So we know that in order to make $200 for the school they must make an actually $400 profit because the company will take half of the money. But we must include the $18 fee.
So in reality the school will have to make a total of $418 to make a $200 profit. Now we just have to find calculate the amount of Magazines sold out of $418.

So 418/20= 20.9 magazines, but you must round to 21 because there's no such thing as selling .9 of a magazine.

So your answer is 21 subscriptions.

Work check:

21 magazines x $20= $420

$420 - $18 (the fee) = 402

$402 / 2 (since the company takes half the profit) = $201

School makes more than $200 profit?
Yes

Answer 2

You are selling magazines to raise money for your school. Each subscription you sell earns $8 for your school. How much money will you raise if you sell 20 subscriptions?

Answer 3

number of subscriptions =x
profit = (20/2) * x - 18
for a profit of 200,
10x - 18 = 200
10x = 218
x = 21.8
therefore, minimum number of tickets = 21

Answer 4

Mimi has big brain