north avenue is 36ft wide when it ends at main st. a 45 foot long diagonal crosswal allows pedestrians to cross main st to or from either corner of north ave. determine the width of main st.

1 answer

Pythagorean Theorem:

a^2 + b^2 = c^2

36^2 + b^2 = 45^2

1296 + b^2 = 2025

b^2 = 729

b = 27 feet