NOCL(g) decomposes to from nitrogen monoxide gas and chlorine gas. The equation is

2NOCL ----> 2NO +Cl2



At a certain temperature the equilibrium constant is 1.60 x 10^-6. Calculate the equilibrium concentrations of all gases if 0.800 moles of NOCL are placed in a 2.00 L container.

I ended up with NOCL^2 = 0.4 mol/L

Cl2 = 3.9 x 10^-3

NO^2 = 2x = 2 x 3.9 x 10-3 =0.0078

7.8 x 10^-3

I am hoping someone could go through the quadratic formula part and let me know if my answers are correct and if not where I took a wrong turn.

2 answers

You ended up with a quadratic?
0.8mol/2L = 0.4 M
..........2NOCl2 ==> 2NO + Cl2
I.........0.40........0.....0
C..........-2x........2x....x
E.......0.40-2x.......2x....x

I ended up with a cubic equation but I found a cubic calculator on the web and it returned 0.00395 for Cl2. It appears your answers are ok.
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