You ended up with a quadratic?
0.8mol/2L = 0.4 M
..........2NOCl2 ==> 2NO + Cl2
I.........0.40........0.....0
C..........-2x........2x....x
E.......0.40-2x.......2x....x
I ended up with a cubic equation but I found a cubic calculator on the web and it returned 0.00395 for Cl2. It appears your answers are ok.
NOCL(g) decomposes to from nitrogen monoxide gas and chlorine gas. The equation is
2NOCL ----> 2NO +Cl2
At a certain temperature the equilibrium constant is 1.60 x 10^-6. Calculate the equilibrium concentrations of all gases if 0.800 moles of NOCL are placed in a 2.00 L container.
I ended up with NOCL^2 = 0.4 mol/L
Cl2 = 3.9 x 10^-3
NO^2 = 2x = 2 x 3.9 x 10-3 =0.0078
7.8 x 10^-3
I am hoping someone could go through the quadratic formula part and let me know if my answers are correct and if not where I took a wrong turn.
2 answers
AgCl is dissolved separatel in pure water and in O.O25 (M) NaCl solution.Find the ratio of concentrations of Ag ion in pure water and in the NaCl solution. The solubility product of AgCl is 1.75 to multiply 1O^-1O
1 answer