Nine times the sum of a number and is at most .
4 answers
Nine times the sum of a number and 27 is at most −16.**
27, would have to go together with a negative number
Nine times the sum of a number and 27 is at most - 16 means:
9 ( c + 27 ) ≤ - 16
9 ∙ c + 9 ∙ 27 ≤ - 16
9 c + 243 ≤ - 16
Subtract 243 of both sides
9 c + 243 - 243 ≤ -16 - 243
9 c ≤ - 259
Divide both sides by 9
c ≤ - 259 / 9
c ≤ - 28.777...
9 ( c + 27 ) ≤ - 16
9 ∙ c + 9 ∙ 27 ≤ - 16
9 c + 243 ≤ - 16
Subtract 243 of both sides
9 c + 243 - 243 ≤ -16 - 243
9 c ≤ - 259
Divide both sides by 9
c ≤ - 259 / 9
c ≤ - 28.777...
I marked the number with c but you can also mark it with x.
9 ( x + 27 ) ≤ - 16
9 x + 9 ∙ 27 ≤ - 16
9 x + 243 ≤ - 16
Subtract 243 of both sides
9 x + 243 - 243 ≤ -16 - 243
9 x ≤ - 259
Divide both sides by 9
x ≤ - 259 / 9
x ≤ - 28.777...
9 ( x + 27 ) ≤ - 16
9 x + 9 ∙ 27 ≤ - 16
9 x + 243 ≤ - 16
Subtract 243 of both sides
9 x + 243 - 243 ≤ -16 - 243
9 x ≤ - 259
Divide both sides by 9
x ≤ - 259 / 9
x ≤ - 28.777...