let the first odd whole number be
n-8
then the others are n-6, n-4 , n-2 , n , n+2, n+4, n+6, and n+8
their sum = 9n
(now wasn't that a clever way to define my numbers?)
9n = 243
n = 27
first = 27-8
last = 27 + 8
and that sum = 27+27 = 54
Nine consecutive odd whole numbers sum to 243. Find the sum if the first and last whole numbers in this nine-addend ser.
1 answer
1 answer