Nila is now x years old. Three yrs ago, her brother ricky was twice as old as she, write rickys age ten yrs frm now in terms of x.

Question

(With solution pls) tnx...

Answer 1

Nila's age = X yrs old, now.
Nila's age = (X-3) yrs old, 3 yrs ago.

Ricky's age = 2(X-3) yrs old, 3 yrs ago.
Ricky-Nila = 2(X-3)-(X-3) = (X-3) yrs
older than Nila.

Ricky's age, now = X + (X-3) = (2x-3)
yrs old.

Ricky's age 10 yrs from now = 10(2x-3) =
(20x-30) yrs old.

Answer 2

Correction:
Ricky's age 10 yrs from now =(2x-3)+10 =
2x+7.

Answer 3

2x+7