Nicotine is not only bad for you (ahem!), but it also acts as a base in aqueous solution:
Kb = 7x10-7 at 298K.
i) Find G per mol of nicotine acting as a base in aqueous solution at 298K.
ii) Find the pH of the solution if the initial [nicotine] = 0.80 M.
iii) Without doing the calculation, explain how you would find Kb and G at body temperature (310K). Be sure to note what other thermodynamic data you would need to do the calculations.
2 answers
Tillie, Merissa, Ben -- please don't change names when you're posting on this forum.
i) Isn't delta G = -RTlnK?
ii)If we denote nicotine by N, then
N ==>NOH+ + H^+
Set up Kb expression.
(H^+) = y
(NOH) = y
(N) = 0.8-y
Solve for y
ii)If we denote nicotine by N, then
N ==>NOH+ + H^+
Set up Kb expression.
(H^+) = y
(NOH) = y
(N) = 0.8-y
Solve for y