To determine the minimum number of hours Nicole needs to practice on each of the last 2 days of the week, we first need to figure out how much practice time is remaining for her.
Nicole needs to practice at least 4 hours in total for the week. She has already practiced two and one third hours. Let's convert this mixed number to an improper fraction for simplicity:
\[ \text{Two and one third} = 2 + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3} \]
Let \( x \) represent the number of hours Nicole needs to practice on each of the remaining 2 days. She will practice a total of \( 2x \) more hours.
The inequality will express that her total practice time, which includes the 2 hours she already practiced plus the \( 2x \) hours she will practice, should be at least 4 hours:
\[ \frac{7}{3} + 2x \ge 4 \]
So, the correct inequality is:
\[ \frac{7}{3} + 2x \ge 4 \]
Written out more clearly for selection, it corresponds to option:
\[ \text{a) two and one third + 2x} \ge 4 \]
Nicole needs to spend at least 4 hours each week practicing the guitar. She has already practiced two and one third hours this week. She wants to split the remaining practice time evenly between the last 2 days of the week. Write an inequality to determine the minimum number of hours she needs to practice on each of the 2 days.
a two and one third + 2x ≥ 4
b two and one third + 2x ≤ 4
c two and one thirdx + 2 ≤ 4
d two and one thirdx + 2 ≥ 4
1 answer
1 answer