Where did the 0.022E23 come from?
How many moles Ni did you find in the 86.4 g Ni?
How many moles Ni(CO)4 does this produce?
Then PV = nRT.
You don't list a T in the problem. Is that room temperature or what?
P = nRT/V and I obtained something like 1.5 or so mols Ni(CO)4.
Ni+4CO=NI(CO)4
this reaction separates nickel from other solid impurities.Starting with 86.4g NI,calculte the pressure of NI(CO)4 in a container of volume
To Drbobb222, after using the formular u gave. PV=nRT moles for NI(CO)4 is 171 and the volume is 4, multiply that rite? Then multiply it to 86.4/6.o22E23 rite?
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