NH4NO3(s)+H2O(l)→NH4NO3(aq) ΔH = +25.7 kJ.

What is the final temperature in a squeezed cold pack that contains 49.0g of NH4NO3 dissolved in 125 mL of water? Assume a specific heat of 4.18J/(g⋅∘C) for the solution, an initial temperature of 28.5∘C, and no heat transfer between the cold pack and the environment.

Please help. I keep getting an increase in heat, which I know isn't right. But I can't seem to figure out where I went wrong. Please explain! Thanks!

2 answers

Instead of me guessing what you did wrong why don't you post your work and let me find the error?
It must not have been all that urgent.
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