NH3(g) + 2O2 (g) = HNO3 (aq) + H2O (l)
How do I calculate the oxidation states of Nitrogen and figure out if it is reduced, oxidized or neither?
2 answers
http://www.chemteam.info/Redox/Redox-Rules.html
Thank you for the link! Here is my answer below. I am not sure if I am figuring it right. Please advise.
NH3(g) + 2O2 (g) = HNO3 (aq) + H2O (l)
N is -3,H3 is +1, 2o2 is 0,
H is +1, N is X ??, O3 is -2, H2O is -2
Therefore X=-2
I am not sure how to figure N. Is it X or is N include NO3?
and it is
Oxidized
NH3(g) + 2O2 (g) = HNO3 (aq) + H2O (l)
N is -3,H3 is +1, 2o2 is 0,
H is +1, N is X ??, O3 is -2, H2O is -2
Therefore X=-2
I am not sure how to figure N. Is it X or is N include NO3?
and it is
Oxidized