Nh3+Cuo=N2+Cu+H2O, 18.1g of nh3 and 90.4g of CuO made to react. (a). Determine the limiting reagent. (b). Which reactant is in excess? (c). Calculate the mass of Cu that forms. (d). Calculate the volume in liter of n2 that form at STP.

Question

Nh3+Cuo=N2+Cu+H2O, 18.1g of nh3 and 90.4g of CuO made to react.  (a). Determine the limiting reagent. (b). Which reactant is in excess?  (c).  Calculate the mass of Cu that forms.  (d).  Calculate the volume in liter of n2 that form at STP.

oobleck · Answer

First, balance the equation. 2NH3 + 3CuO = N2 + 3Cu + 3H2O Now convert your grams to moles, and see which gets used up first. For (d), recall that 1 mole of N2 occupies 22.4L of space.

Meng · Answer

Aque