Next step, multiply both sides by (.01-x)
.012(.01-x)=.01x+x^2
gather terms, put in standard binomial form, use the quadratic equation, and solve for x.
is the standard binomial x^2+.022x-1.2x10^-4
2 answers
yes. That is the correct quadratic equation. Now solve for x. Then (H^+) = 0.01 + x and pH = -log(H^+).
yes.