5 n + 10 d + 25 q = 185
d = 2 q
n = 2 d -2 = 4 q - 2
so
5 (4q-2) + 10(2q) + 25q = 185
ok from there?
nestor has nickels, dimes, and quarters amounting to $1.85. if he has twice as many dimes as quarters, and the number of nickels is two less than twice the number of dimes, how many quarters does he have?
2 answers
1.85= 0.05∗(4q−2)+0.25q+ 0.10∗2q1.85= 0.05∗(4q−2)+0.25q+ 0.10∗2q
1.85= 0.2q−0.1+0.25q+ 0.2q1.85= 0.2q−0.1+0.25q+ 0.2q
1.85+0.1= 0.65q1.85+0.1= 0.65q
1.95= 0.65q1.95= 0.65q
3= q
1.85= 0.2q−0.1+0.25q+ 0.2q1.85= 0.2q−0.1+0.25q+ 0.2q
1.85+0.1= 0.65q1.85+0.1= 0.65q
1.95= 0.65q1.95= 0.65q
3= q