Neptunium 239
93 Np has a decay constant of 3.40 ×10-6 s-1. A 3.0-mg sample of Np-239 is
prepared. The activity of the Np-239 sample, in Ci, is
3 answers
Ok, take the last I gave you, and divide by 3.7E10
how do I solve it?
activityinCi=decayconstant*avadgrado's number*molesNp/3.7E10
= 3.4E-6*3/239*6.023E23/3.7E10
= 3.4E-6*3/239*6.023E23/3.7E10
1 answer