Ok. Here is what I am thinking. As the student, you will need to see if I am also thinking this correctly.
30. If the the block weighs 40 pounds now (after 2 hours), and the block losses 1/3 of its weight every hour, then it has lost 2/3 (2 hours of losing 1/3 is 2/3) so far. It has 1/3 left (40 pounds). If 40 is 1/3 of its weight, then you can figure out how much it started with. 1/3 + 1/3 + 1/3 = the starting weight. 40 + 40 + 40 = ? (I've done more than enough). You can finish thes up for me.
48. Commutative property means that you can do it more than one way. The sentence stated that you ate AND had dinner. It didn't state in which order you did it in. So is it commutative?
50. To figure this one out, I noticed that you were given two year's profits (1989 and 1994). By subtracting the two profits, I saw that there was a $3760 increase in 1994 than 1989. I originally agreed with you on your answer, but as I was typing this I asked myself what year is it wanting? 2003 is not 5 years difference. It is 9. You may need to add $3760 twice. I have not done that, so please see if I'm right. I do not think A is the correct answer.
Need help with these 3, with work shown please---
30. A block of ice loses one-third of its weight every hour. After 2 hours, the block weighs 40 pounds. How much did the block of ice weigh to begin with?
48. Does the Commutative Property apply to this situation? I ate dinner and read a book.
50. You work for FunMath, Inc. It is your job to describe the financial future of your beloved company. You just started, and the last person didn't do a good job of record keeping. In fact, the last person only has two years data. After going through all the old files, you only found the following information: in 1989 FunMath Inc. made a profit of $3,720.00 and in 1994 FunMath, Inc. made a profit of $7,480. Your boss would like to know what 2003's profit will be based on this limited information. Assume that FunMath's profits act linearly.
a. $11,240.00
b. $752.00
c. $14,248.00
I think this might be A
Thanks
-MC
4 answers
just my thought on #30
Since it loses 1/3 of its weight each hour and after 2 hours it weighs 40 lbs,
then one hour ago it must have weighed 40 ÷ (2/3) lbs or 60 lbs. (check take 1/3 of 60 and subtract)
then 2 hours ago it must have weighed 60 ÷ (2/3) or 90 lbs.
check: take 1/3 of 90 away ---> 60
take 1/3 of 60 away --> 40, my answer is correct.
Since it loses 1/3 of its weight each hour and after 2 hours it weighs 40 lbs,
then one hour ago it must have weighed 40 ÷ (2/3) lbs or 60 lbs. (check take 1/3 of 60 and subtract)
then 2 hours ago it must have weighed 60 ÷ (2/3) or 90 lbs.
check: take 1/3 of 90 away ---> 60
take 1/3 of 60 away --> 40, my answer is correct.
I believe Reiny may be right. I sometimes miss the "tricky" aspect of the questions.
30. 90 lbs
48. yes
50. c, $14,248.00
48. yes
50. c, $14,248.00