write it as
y = 3x + 4x^-1
y' = 3 - 4x^-2
y'' = 8x^-3 or 8/x^3
Need help with the following along with all steps.
Find y" for y = 3x + 4/x
2 answers
Thank you so much for your help. Now that I look at it more closely. I understand what I wasn't seeing!