Asked by Stacy
Need help setting up equation so I can solve it.
Jose has $6.70 in an assortment of coins. If he has 3 more quarters than pennies,11 more dimes than pennies, and 2.5 times as many nickels as pennies, how many of each type of coin does he have?
Jose has $6.70 in an assortment of coins. If he has 3 more quarters than pennies,11 more dimes than pennies, and 2.5 times as many nickels as pennies, how many of each type of coin does he have?
Answers
Answered by
Steve
Just write down what they have told you.
q = p+3
d = p+11
n = 5/2 p
p+5n+10d+25q = 670
Now just solve for p,n,d,q
If that looks hard, solve for p first. That gives
p + 5(5/2 p) + 10(p+11) + 25(p+3) = 670
Once you have p, then you can easily figure the others...
q = p+3
d = p+11
n = 5/2 p
p+5n+10d+25q = 670
Now just solve for p,n,d,q
If that looks hard, solve for p first. That gives
p + 5(5/2 p) + 10(p+11) + 25(p+3) = 670
Once you have p, then you can easily figure the others...
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