Asked by Anonymous
Need guidance on how to solve this one
How many liters of water vapor can be produced if 108 grams of methane gas are conbusted at 312K and 98 atm. CH4 + 202 = C02 + 2H20
How many liters of water vapor can be produced if 108 grams of methane gas are conbusted at 312K and 98 atm. CH4 + 202 = C02 + 2H20
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.