Need an answer to this Calculus Question. I keep getting this type of question wrong. Thanks.

Differentiate the Function:

y = (3x-1)^2(2-x^4)^2

y =

1 answer

do is as a uv problem

d(uv)=vdu+udv

y'=2(3x-1)(3) [2-x^4)^2 + 2(2-x^4)(-4x^3)(3x-1)^2

have fun gathering terms.