ne kilogram of ice of density 1000 kg m–3 is frozen in the shape of a cube. The diameter of a water molecule is 10–10 m. What is the difference in the orders of magnitude of the length of one side of the ice cube and the diameter of a water molecule?

Question

please and thank u

Answer 1

The volume of 1kg ice is:
V = mass/density = 1/1000 = 10⁻³ m³

A cube with sides of length L has a volume = L³

So for the ice cube:
L³ = 10⁻³
L = ∛(10⁻³) = 10⁻¹m

The ratio (length of ice cube)/(diameter of molecule)
= (10⁻¹)/(10⁻¹⁰)
= 10⁹

We say the length of a side of the ice cube is
*** 9 orders of magnitude ***
bigger than the diameter of the water molecule.

Or we can say there are 9 orders of magnitude difference between the length of one side of the ice cube and the diameter of a water molecule.

Answer 2

flirty me/ supercute -- please keep the same name for your posts.

Answer 3

use the second phrase.