To calculate the kinetic energy (KE) of the suitcase just before it hits the floor, you can use the formula KE = 1/2 * m * v^2, where m is the mass and v is the velocity (speed) of the suitcase.
Plugging in the given values:
m = 14 kg
v = 2.7 m/s
KE = 1/2 * 14 kg * (2.7 m/s)^2
= 1/2 * 14 kg * 7.29 m^2/s^2
= 51.03 J
Therefore, the suitcase has a kinetic energy of 51.03 Joules just before it hits the floor.
Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?
KE=12mv2
(1 point)
Responses
102.06 J
102.06 J
51.03 J
51.03 J
204.12 J
204.12 J
18.9 J
1 answer
2 answers