Let's go through this step-by-step:
Part 1
Fractions Reported:
- Brad: \( \frac{4}{5} \)
- Alice: \( \frac{1}{2} \)
- Andre: \( \frac{4}{6} = \frac{2}{3} \) (simplified)
1. Which of these players made the greatest fraction of goals?
To compare the fractions, let's convert them to a common denominator or decimal form:
- \( \frac{4}{5} = 0.8 \)
- \( \frac{1}{2} = 0.5 \)
- \( \frac{2}{3} \approx 0.67 \)
Conclusion: Brad made the greatest fraction of goals with \( \frac{4}{5} \).
2. Calculate how many goals Sydney must make:
If Sydney wants to achieve the same fraction \( \frac{4}{5} \) making 10 shots, we set up the equation:
\[ \frac{4}{5} = \frac{x}{10} \]
Where \( x \) is the number of goals she must make. We solve for \( x \):
\[ 4 \times 10 = 5x \ 40 = 5x \ x = \frac{40}{5} = 8 \]
Sydney must make 8 goals.
3. Find two possible fractions for Tom:
Tom wants to maintain the same fraction \( \frac{2}{3} \) that Andre had, while taking more than 20 kicks.
Let \( y \) be the number of goals Tom makes and \( n \) be the number of kicks he takes:
\[ \frac{2}{3} = \frac{y}{n} \]
Two possible fractions, provided \( n > 20 \), can be found by selecting multiples of 3 (for \( n \)) and corresponding \( y \):
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If \( n = 24 \): \[ \frac{y}{24} = \frac{2}{3} \Rightarrow y = \frac{2}{3} \times 24 = 16 \ \Rightarrow Tom can make \( \frac{16}{24} \) \]
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If \( n = 27 \): \[ \frac{y}{27} = \frac{2}{3} \Rightarrow y = \frac{2}{3} \times 27 = 18 \ \Rightarrow Tom can make \( \frac{18}{27} \) \]
Therefore, two possible fractions are \( \frac{16}{24} \) and \( \frac{18}{27} \).
4. Finding equivalent fractions to \( \frac{1}{4} \):
Three fractions equivalent to \( \frac{1}{4} \) can be made by multiplying the numerator and the denominator by the same non-zero integer:
- \( \frac{2}{8} \)
- \( \frac{3}{12} \)
- \( \frac{5}{20} \)
5. Players for Equal Teams:
For the coach to create equal teams of 6 with no one left out from a total of 32 players, the total number of players must be a multiple of 6.
To find suitable numbers, we can do:
\[ 6, 12, 18, 24, 30 \]
As these are all multiples of 6, each allows equal team formation where no one is left out.
Conclusion: Possible numbers of players who must show up to practice = {6, 12, 18, 24, 30}.
For a total of 32 players specifically, they cannot make groups of 6 as 32 is not a multiple of 6; hence adjustments would be necessary.