The word that describes the probability of Nachelle pulling out a cherry chew is "likelihood".
To find the probability of landing on red, we add up the frequency of all the red outcomes (4) and divide it by the total number of outcomes (4+3+20+14+16=57):
4/57 = 0.070 (rounded to three decimal places)
To express this as a percentage, we multiply by 100:
0.070 x 100 = 7%
Therefore, the probability of the next spin landing on red is 7% to the nearest whole number.
Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red, Frequency: 4
Color: Blue, Frequency: 3
Color: Green, Frequency: 20
Color: Yellow, Frequency: 14
Color: Purple, Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red
Frequency: 4
Color: Blue
Frequency: 3
Color: Green
Frequency: 20
Color: Yellow
Frequency: 14
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
32 answers
In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Tallulah sets up a website where players can buy and sell these costumes online. Information about the number of people who visited the website and the number of costumes purchased in a single day is listed below.
171 visitors purchased no costume.
148 visitors purchased exactly one costume.
34 visitors purchased more than one costume.
Based on these results, express the probability that the next person will purchase more than one costume as a fraction in simplest form.
171 visitors purchased no costume.
148 visitors purchased exactly one costume.
34 visitors purchased more than one costume.
Based on these results, express the probability that the next person will purchase more than one costume as a fraction in simplest form.
To find the probability, we need to add up the number of visitors who purchased more than one costume and divide it by the total number of visitors:
P(more than one costume) = 34 / (171 + 148 + 34)
Simplifying the denominator:
P(more than one costume) = 34 / 353
This fraction is already in simplest form, so the probability that the next person will purchase more than one costume is 34/353.
P(more than one costume) = 34 / (171 + 148 + 34)
Simplifying the denominator:
P(more than one costume) = 34 / 353
This fraction is already in simplest form, so the probability that the next person will purchase more than one costume is 34/353.
Madison has a bag that contains strawberry chews, lemon chews, and lime chews. She performs an experiment. Madison randomly removes a chew from the bag, records the result, and returns the chew to the bag. Madison performs the experiment 26 times. The results are shown below:
A strawberry chew was selected 10 times.
A lemon chew was selected 14 times.
A lime chew was selected 2 times.
Based on these results, express the probability that the next chew Madison removes from the bag will be a flavor other than lemon as a percent to the nearest whole number.
A strawberry chew was selected 10 times.
A lemon chew was selected 14 times.
A lime chew was selected 2 times.
Based on these results, express the probability that the next chew Madison removes from the bag will be a flavor other than lemon as a percent to the nearest whole number.
To find the probability that the next chew Madison removes from the bag will be a flavor other than lemon, we need to add up the number of times a strawberry or lime chew was selected and divide it by the total number of selections:
P(strawberry or lime) = (10 + 2) / 26
Simplifying the numerator:
P(strawberry or lime) = 12 / 26
Converting to a percentage:
P(strawberry or lime) = 46% (rounded to the nearest whole number)
Therefore, the probability that the next chew Madison removes from the bag will be a flavor other than lemon is 46%.
P(strawberry or lime) = (10 + 2) / 26
Simplifying the numerator:
P(strawberry or lime) = 12 / 26
Converting to a percentage:
P(strawberry or lime) = 46% (rounded to the nearest whole number)
Therefore, the probability that the next chew Madison removes from the bag will be a flavor other than lemon is 46%.
Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red
Frequency: 4
Color: Blue
Frequency: 3
Color: Green
Frequency: 20
Color: Yellow
Frequency: 14
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red
Frequency: 4
Color: Blue
Frequency: 3
Color: Green
Frequency: 20
Color: Yellow
Frequency: 14
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
Color: Red
Frequency: 4
Color: Blue
Frequency: 3
Color: Green
Frequency: 20
Color: Yellow
Frequency: 14
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red
Frequency: 4
Color: Blue
Frequency: 3
Color: Green
Frequency: 20
Color: Yellow
Frequency: 14
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
The word that describes the probability of Nachelle pulling out a cherry chew is "likelihood".
To find the probability of landing on red, we add up the frequency of all the red outcomes (4) and divide it by the total number of outcomes (4+3+20+14+16=57):
4/57 = 0.070 (rounded to three decimal places)
To express this as a percentage, we multiply by 100:
0.070 x 100 = 7%
Therefore, the probability of the next spin landing on red is 7% to the nearest whole number.
To find the probability of landing on red, we add up the frequency of all the red outcomes (4) and divide it by the total number of outcomes (4+3+20+14+16=57):
4/57 = 0.070 (rounded to three decimal places)
To express this as a percentage, we multiply by 100:
0.070 x 100 = 7%
Therefore, the probability of the next spin landing on red is 7% to the nearest whole number.
Nachelle has a bag of candy full of 1 strawberry chew and 19 cherry chews that she eats one at a time. Which word or phrase describes the probability that she reaches in without looking and pulls out a cherry chew?
Color: Red
Frequency: 19
Color: Blue
Frequency: 20
Color: Green
Frequency: 14
Color: Yellow
Frequency: 8
Color: Purple
Frequency: 10
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
Color: Red
Frequency: 19
Color: Blue
Frequency: 20
Color: Green
Frequency: 14
Color: Yellow
Frequency: 8
Color: Purple
Frequency: 10
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
The word that describes the probability of Nachelle pulling out a cherry chew is "likelihood".
To find the probability of landing on red, we need to know the frequency of the red outcome. However, the color red is not listed in the given information, so we cannot determine this probability.
Therefore, we cannot express the probability of the next spin landing on red as a percent to the nearest whole number.
To find the probability of landing on red, we need to know the frequency of the red outcome. However, the color red is not listed in the given information, so we cannot determine this probability.
Therefore, we cannot express the probability of the next spin landing on red as a percent to the nearest whole number.
A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is spun several times, and the results are recorded below:
Color: Red
Frequency: 19
Color: Blue
Frequency: 20
Color: Green
Frequency: 14
Color: Yellow
Frequency: 8
Color: Purple
Frequency: 10
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
Color: Red
Frequency: 19
Color: Blue
Frequency: 20
Color: Green
Frequency: 14
Color: Yellow
Frequency: 8
Color: Purple
Frequency: 10
Based on these results, express the probability that the next spin will land on red as a percent to the nearest whole number.
To find the probability of landing on red, we first need to calculate the total number of spins:
Total frequency = 19 + 20 + 14 + 8 + 10 = 71
Next, we find the probability by dividing the frequency of red by the total frequency:
P(red) = 19 / 71
Converting to a percentage:
P(red) = 26.76% (rounded to the nearest whole number)
Therefore, the probability that the next spin will land on red is 27% to the nearest whole number.
Total frequency = 19 + 20 + 14 + 8 + 10 = 71
Next, we find the probability by dividing the frequency of red by the total frequency:
P(red) = 19 / 71
Converting to a percentage:
P(red) = 26.76% (rounded to the nearest whole number)
Therefore, the probability that the next spin will land on red is 27% to the nearest whole number.
Rajani has a bag that contains strawberry chews, cherry chews, and lime chews. She performs an experiment. Rajani randomly removes a chew from the bag, records the result, and returns the chew to the bag. Rajani performs the experiment 38 times. The results are shown below:
A strawberry chew was selected 23 times.
A cherry chew was selected 4 times.
A lime chew was selected 11 times.
Based on these results, express the probability that the next chew Rajani removes from the bag will be strawberry or cherry as a fraction in simplest form.
A strawberry chew was selected 23 times.
A cherry chew was selected 4 times.
A lime chew was selected 11 times.
Based on these results, express the probability that the next chew Rajani removes from the bag will be strawberry or cherry as a fraction in simplest form.
To find the probability that the next chew Rajani removes from the bag will be strawberry or cherry, we need to add up the number of times a strawberry or cherry chew was selected and divide it by the total number of selections:
P(strawberry or cherry) = (23 + 4) / 38
Simplifying the numerator:
P(strawberry or cherry) = 27 / 38
This fraction is already in simplest form, so the probability that the next chew Rajani removes from the bag will be strawberry or cherry is 27/38.
P(strawberry or cherry) = (23 + 4) / 38
Simplifying the numerator:
P(strawberry or cherry) = 27 / 38
This fraction is already in simplest form, so the probability that the next chew Rajani removes from the bag will be strawberry or cherry is 27/38.
There is a spinner with 9 equal areas, numbered 1 through 9. If the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?
To solve this, we need to find the numbers which are multiples of both 2 and 3. These numbers are 6 and its multiples (6, 12), and we can see that there are two of them on the spinner. Therefore, the probability of spinning a multiple of 2 and a multiple of 3 is:
P = number of desired outcomes / total number of outcomes
P = 2 / 9
So the probability of spinning a multiple of 2 and a multiple of 3 is 2/9.
P = number of desired outcomes / total number of outcomes
P = 2 / 9
So the probability of spinning a multiple of 2 and a multiple of 3 is 2/9.
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 3 and a multiple of 5?
To solve this problem, we need to find the numbers which are multiples of both 3 and 5. The smallest such number is 15, and its multiples are 15, 30, and 45. We can see that there is only one of these on the spinner.
Therefore, the probability of spinning a multiple of 3 and a multiple of 5 is:
P = number of desired outcomes / total number of outcomes
P = 1 / 15
So the probability of spinning a multiple of 3 and a multiple of 5 is 1/15.
Therefore, the probability of spinning a multiple of 3 and a multiple of 5 is:
P = number of desired outcomes / total number of outcomes
P = 1 / 15
So the probability of spinning a multiple of 3 and a multiple of 5 is 1/15.
There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 5 and a multiple of 2?
To solve this problem, we need to find the numbers which are multiples of both 5 and 2 (or multiples of 10). The only multiple of 10 on the spinner is 10 itself.
Therefore, the probability of spinning a multiple of 5 and a multiple of 2 is:
P = number of desired outcomes / total number of outcomes
P = 1 / 15
So the probability of spinning a multiple of 5 and a multiple of 2 is 1/15.
Therefore, the probability of spinning a multiple of 5 and a multiple of 2 is:
P = number of desired outcomes / total number of outcomes
P = 1 / 15
So the probability of spinning a multiple of 5 and a multiple of 2 is 1/15.
A bag contains 4 red marbles, 5 blue marbles and 3 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be blue?
To find the probability of drawing two blue marbles, we need to use the formula for the probability of independent events:
P(A and B) = P(A) x P(B)
where P(A) is the probability of the first event and P(B) is the probability of the second event, given that the first event has occurred.
The probability of drawing a blue marble on the first draw is 5/12, since there are 5 blue marbles out of a total of 12 marbles.
After the first blue marble is drawn, there will be one less blue marble and one less marble in total. So the probability of drawing a second blue marble is 4/11.
Using the formula, the probability of drawing two blue marbles is:
P(both blue) = (5/12) x (4/11)
Simplifying:
P(both blue) = 5/33
So the exact probability of drawing two blue marbles is 5/33.
P(A and B) = P(A) x P(B)
where P(A) is the probability of the first event and P(B) is the probability of the second event, given that the first event has occurred.
The probability of drawing a blue marble on the first draw is 5/12, since there are 5 blue marbles out of a total of 12 marbles.
After the first blue marble is drawn, there will be one less blue marble and one less marble in total. So the probability of drawing a second blue marble is 4/11.
Using the formula, the probability of drawing two blue marbles is:
P(both blue) = (5/12) x (4/11)
Simplifying:
P(both blue) = 5/33
So the exact probability of drawing two blue marbles is 5/33.
A bag contains 8 red marbles, 3 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be blue?
To find the probability of drawing two blue marbles, we need to use the formula for the probability of independent events:
P(A and B) = P(A) x P(B)
where P(A) is the probability of the first event and P(B) is the probability of the second event, given that the first event has occurred.
The probability of drawing a blue marble on the first draw is 3/13, since there are 3 blue marbles out of a total of 13 marbles. After the first blue marble is drawn, there will be one less blue marble and one less marble in total. So the probability of drawing a second blue marble is 2/12 (or 1/6), since there are now only 2 blue marbles left out of a total of 12 marbles.
Using the formula, the probability of drawing two blue marbles is:
P(both blue) = (3/13) x (1/6)
Simplifying:
P(both blue) = 1/26
So the exact probability of drawing two blue marbles is 1/26.
P(A and B) = P(A) x P(B)
where P(A) is the probability of the first event and P(B) is the probability of the second event, given that the first event has occurred.
The probability of drawing a blue marble on the first draw is 3/13, since there are 3 blue marbles out of a total of 13 marbles. After the first blue marble is drawn, there will be one less blue marble and one less marble in total. So the probability of drawing a second blue marble is 2/12 (or 1/6), since there are now only 2 blue marbles left out of a total of 12 marbles.
Using the formula, the probability of drawing two blue marbles is:
P(both blue) = (3/13) x (1/6)
Simplifying:
P(both blue) = 1/26
So the exact probability of drawing two blue marbles is 1/26.
A bag contains 3 red marbles, 7 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be green?
To find the probability of drawing three green marbles, we need to use the formula for the probability of independent events:
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a green marble on the first draw is 8/18, since there are 8 green marbles out of a total of 18 marbles. After the first green marble is drawn, there will be one less green marble and one less marble in total. So the probability of drawing a second green marble is 7/17, since there are now only 7 green marbles left out of a total of 17 marbles. Finally, after the second green marble is drawn, there will be two less green marbles and two less marbles in total. So the probability of drawing a third green marble is 6/16 (or 3/8), since there are now only 6 green marbles left out of a total of 16 marbles.
Using the formula, the probability of drawing three green marbles is:
P(all green) = (8/18) x (7/17) x (3/8)
Simplifying:
P(all green) = 0.07352941176....
So the exact probability of drawing three green marbles is approximately 0.0735 (rounded to four decimal places).
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a green marble on the first draw is 8/18, since there are 8 green marbles out of a total of 18 marbles. After the first green marble is drawn, there will be one less green marble and one less marble in total. So the probability of drawing a second green marble is 7/17, since there are now only 7 green marbles left out of a total of 17 marbles. Finally, after the second green marble is drawn, there will be two less green marbles and two less marbles in total. So the probability of drawing a third green marble is 6/16 (or 3/8), since there are now only 6 green marbles left out of a total of 16 marbles.
Using the formula, the probability of drawing three green marbles is:
P(all green) = (8/18) x (7/17) x (3/8)
Simplifying:
P(all green) = 0.07352941176....
So the exact probability of drawing three green marbles is approximately 0.0735 (rounded to four decimal places).
A bag contains 8 red marbles, 3 blue marbles and 5 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be green?
To find the probability of drawing three green marbles, we need to use the formula for the probability of independent events:
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a green marble on the first draw is 5/16, since there are 5 green marbles out of a total of 16 marbles. After the first green marble is drawn, there will be one less green marble and one less marble in total. So the probability of drawing a second green marble is 4/15, since there are now only 4 green marbles left out of a total of 15 marbles. Finally, after the second green marble is drawn, there will be two less green marbles and two less marbles in total. So the probability of drawing a third green marble is 3/14, since there are now only 3 green marbles left out of a total of 14 marbles.
Using the formula, the probability of drawing three green marbles is:
P(all green) = (5/16) x (4/15) x (3/14)
Simplifying:
P(all green) = 0.01428571428....
So the exact probability of drawing three green marbles is approximately 0.0143 (rounded to four decimal places).
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a green marble on the first draw is 5/16, since there are 5 green marbles out of a total of 16 marbles. After the first green marble is drawn, there will be one less green marble and one less marble in total. So the probability of drawing a second green marble is 4/15, since there are now only 4 green marbles left out of a total of 15 marbles. Finally, after the second green marble is drawn, there will be two less green marbles and two less marbles in total. So the probability of drawing a third green marble is 3/14, since there are now only 3 green marbles left out of a total of 14 marbles.
Using the formula, the probability of drawing three green marbles is:
P(all green) = (5/16) x (4/15) x (3/14)
Simplifying:
P(all green) = 0.01428571428....
So the exact probability of drawing three green marbles is approximately 0.0143 (rounded to four decimal places).
can you write that answer as a fraction in simplest form?
We want to convert 0.0143 to a fraction in simplest form.
We can do this by writing 0.0143 as the fraction 143/10000 (by moving the decimal point four places to the right).
To simplify this fraction, we can divide the numerator and denominator by their greatest common factor, which is 143:
143/10000 = (1/10000) x 143/1 = 143/10000
So the probability of drawing three green marbles is 143/10000 as a fraction in simplest form.
We can do this by writing 0.0143 as the fraction 143/10000 (by moving the decimal point four places to the right).
To simplify this fraction, we can divide the numerator and denominator by their greatest common factor, which is 143:
143/10000 = (1/10000) x 143/1 = 143/10000
So the probability of drawing three green marbles is 143/10000 as a fraction in simplest form.
A bag contains 8 red marbles, 4 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be red?
To find the probability of drawing three red marbles, we need to use the formula for the probability of independent events:
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a red marble on the first draw is 8/19, since there are 8 red marbles out of a total of 19 marbles. After the first red marble is drawn, there will be seven less red marbles and two less
P(A and B and C) = P(A) x P(B) x P(C)
where P(A) is the probability of the first event, P(B) is the probability of the second event, given that the first event has occurred, and P(C) is the probability of the third event, given that the first two events have occurred.
The probability of drawing a red marble on the first draw is 8/19, since there are 8 red marbles out of a total of 19 marbles. After the first red marble is drawn, there will be seven less red marbles and two less
Answer this.
A bag contains 8 red marbles, 4 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be red?
A bag contains 8 red marbles, 4 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be red?