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_ Na2O + _ CaBr2 → _ NaBr + _ CaO

a
1:2:1:1
b
2:1:1:1
c
1:1:2:1
d
1:1:1:2

1 answer

To balance the chemical equation \( \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \), we can follow these steps:

  1. Identify the components:

    • Reactants: \( \text{Na}_2\text{O} \) and \( \text{CaBr}_2 \)
    • Products: \( \text{NaBr} \) and \( \text{CaO} \)

  2. Write the unbalanced equation: \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO} \]

  3. Count the atoms of each element on both sides:

    • Left Side:

      • Na: 2 (from \( \text{Na}_2\text{O} \))
      • O: 1 (from \( \text{Na}_2\text{O} \))
      • Ca: 1 (from \( \text{CaBr}_2 \))
      • Br: 2 (from \( \text{CaBr}_2 \))

    • Right Side (initially):

      • Na: 1 (from \( \text{NaBr} \))
      • O: 1 (from \( \text{CaO} \))
      • Ca: 1 (from \( \text{CaO} \))
      • Br: 1 (from \( \text{NaBr} \))

  4. Balance the reactants and products:

    • To balance Na, since there are 2 Na in the reactants but only 1 in the products, we place a coefficient of 2 in front of \( \text{NaBr} \): \[ \text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2 \text{NaBr} + \text{CaO} \]

  5. Recount the atoms after this adjustment:

    • Left Side:

      • Na: 2
      • O: 1
      • Ca: 1
      • Br: 2

    • Right Side:

      • Na: 2 (from \( 2 , \text{NaBr} \))
      • O: 1 (from \( \text{CaO} \))
      • Ca: 1 (from \( \text{CaO} \))
      • Br: 2 (from \( 2 , \text{NaBr} \))

  6. Final balanced equation: \[ 1 , \text{Na}_2\text{O} + 1 , \text{CaBr}_2 \rightarrow 2 , \text{NaBr} + 1 , \text{CaO} \]

This means the coefficients are 1:1:2:1.

Therefore, the correct answer is: c 1:1:2:1.