N2H4+2H2O2->N2+4H2O
a) If you start with 23.0 g of hydrazine and 23.0g of hydrogen peroxide, which substance is the limiting reactant?
b) How much of the other chemical is left unreacted?
c) Assuming 75% yield, how many grams of water are formed?
I have no idea how to do this problem. I can't remember anything chemistry and need someone to walk me through it please.
2 answers
Correction: Under part a, that is supposed to be 25.0 grams hydrogen peroxide.
You need to compute how many moles of each you have. Then, the balanced equation tells you that you need twice the moles of peroxide. Do you have more than twice? if so, you have an excess of proxide. If you have less than twice the moles, you have a deficit of peroxide.
If you then use the deficit (limiting) reactant as the starting number of moles, you know how many moles of product you should have gotten. However, multipy that by .75 as it was not efficient conversion.
If you then use the deficit (limiting) reactant as the starting number of moles, you know how many moles of product you should have gotten. However, multipy that by .75 as it was not efficient conversion.
4 answers