To balance the equation when changing from 2H₂ to 3H₂, let's first write the unbalanced equation:
\[ 3H_2 + O_2 \rightarrow ? \]
To balance the hydrogen atoms, since there are 3 H₂ molecules, there will be 6 hydrogen atoms total. Therefore, to produce water (H₂O), we need 6 hydrogen atoms, which means we would produce 3 molecules of water (H₂O), because each water molecule contains 2 hydrogen atoms:
\[ 3H_2 + O_2 \rightarrow 3H_2O \]
Next, we need to balance the oxygen. In this case, we have one O₂ molecule, which contributes 2 oxygen atoms and matches with the 3 water molecules that also contain 3 oxygen atoms (one for each water molecule).
After rebalancing the whole equation, we would get:
\[ 3H_2 + O_2 \rightarrow 3H_2O \]
The correct statements based on this balanced equation are:
- Each oxygen molecule will combine with 3 hydrogen molecules to produce 3 molecules of water with no leftover molecules.
Thus, from the given options, the correct statement is: "The equation will produce three molecules of water."